wmras
Well-Known Member
- First Name
- Bill
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- Apr 6, 2020
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- Oregon
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Normally, we do not think too much about wire resistance, but a 40-amp circuit generates a lot of heat loss. Power (watts, heat) = amperes squared times resistance (W = I^2 x R).My electrician just told me he doesn't think that 20 ft would make that much of a difference but is willing to try...given the 70 ft of wire I have currently.
For example, the power loss at 40A at 100 ft. equals:
#4-gauge wire Watts = 40A x 40A x 100 x 2 x 0.0003
= 96 watts (~1 watt/ft.)
#6-gauge wire Watts = 40A x 40A x 100 x 2 x 0.0005
= 160 watts (~1.6 watts/ft.)
#8-gauge wire Watts = 40A x 40A x 100 x 2 x 0.0008
= 256 watts (~2.6 watts/ft.)
Your first reaction be that is not much loss, but how long can you hold a lit five watt light bulb in your hand?
Bottom line, larger wire, solid connections, and great receptacle/plug contacts reduce loss, heat, and risk of fire.
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