How the Taycan Recovers Energy While Driving - Porsche Newsroom

Jhenson29

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Lol at the first line, right off the bat.

The Taycan generates new energy when braking.
 

Jhenson29

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I guess this line should help settle what is meant by the “90% of braking is done with regen” as well as when the friction brakes are added:

Around 90 percent of everyday braking is 100 percent electric,
 

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I guess this line should help settle what is meant by the “90% of braking is done with regen” as well as when the friction brakes are added:
"Around 90 percent of everyday braking is 100 percent electric"

It makes perfect sense, but I really can't help but hear this clip in my head after reading that quote:

 


Jhenson29

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"Around 90 percent of everyday braking is 100 percent electric"

It makes perfect sense, but I really can't help but heat this clip in my head after reading that quote:

That clip would be good for the PCM.
 

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Lol at the first line, right off the bat.
:CWL: Definitely not written, or even proofread by engineers or physicists. From the article:
Kinetic braking energy increases twice as fast as speed – double the speed means four times the recuperation.
For those who don't know, kinetic energy is proportional to speed squared (to the power of 2), rather than double. So 4 times the speed is 16 times (4^2) the kinetic energy, not 8 (4*2). It just happens to work out that 2 to the power of 2 gives the same result as 2 doubled.
 

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I guess this line should help settle what is meant by the “90% of braking is done with regen” as well as when the friction brakes are added:
90% of total energy dissipated by braking, 90% of the total duration, 90% of the times you press the brake pedal? Gotta love marketing - sounds impressive, but actually informs very little.
 

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:CWL: Definitely not written, or even proofread by engineers or physicists. From the article:

For those who don't know, kinetic energy is proportional to speed squared (to the power of 2), rather than double. So 4 times the speed is 16 times (4^2) the kinetic energy, not 8 (4*2). It just happens to work out that 2 to the power of 2 gives the same result as 2 doubled.
What he said :rolleyes:
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